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多边形三角剖分的最低得分（区间DP）

链接

class Solution:
    def minScoreTriangulation(self, values: List[int]) -> int:
        n = len(values)

        f = [[0] * n for _ in range(n)]
        for i in range(n - 3, -1, -1):
            for j in range(i + 2, n):
                f[i][j] = min(f[i][k] + f[k][j] + values[i] * values[j] * values[k] 
                for k in range(i + 1, j))
        return f[0][n - 1]

合并石头的最低成本（区间DP）

链接

class Solution:
    def mergeStones(self, stones: List[int], k: int) -> int:
        n = len(stones)
        if (n - 1) % (k - 1):
            return -1
        s = list(accumulate(stones, initial=0))
        f = [[0] * n for _ in range(n)]
        for i in range(n - 1, -1, -1):
            for j in range(i + 1, n):
                f[i][j] = min(f[i][m] + f[m + 1][j] for m in range(i, j, k - 1))
                if not (j - i) % (k - 1):
                    f[i][j] += s[j + 1] - s[i]
        
        return f[0][-1]
                

代码007普通

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