本文介绍: iOS中对于指定高度弹出页面的设想1.首先需要指定弹出页面的高度:/** 页面高度 */ func groundHeight() -> CGFloat { return SlidePopViewController.windowSize.height-100 } /// 展示 class func show(_ controller: UIViewController) { let vc = SlidePopVie
iOS指定高度弹出页、可拖动,点击空白包括状态栏收回
/**
页面高度
*/
func groundHeight() -> CGFloat {
return SlidePopViewController.windowSize.height-100
}
/// 展示
class func show(_ controller: UIViewController) {
let vc = SlidePopViewController()
vc.modalTransitionStyle = .coverVertical
vc.modalPresentationStyle = .overCurrentContext
controller.present(vc, animated: false) {
let size = SlidePopViewController.windowSize
vc.view.frame = CGRect(x: 0, y: size.height, width: size.width, height: vc.groundHeight())
UIView.animate(withDuration: 0.25, delay: 0, options: .curveEaseInOut, animations: {
vc.view.frame = CGRect(x: 0, y: size.height-vc.groundHeight(), width: size.width, height: vc.groundHeight())
}, completion: nil)
}
}
let gesture = UIPanGestureRecognizer(target: self, action: #selector(slidePanAction(_:)))
gesture.delegate = self
view.addGestureRecognizer(gesture)
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
if let point = touches.first?.location(in: keyWindow) {
if !view.frame.contains(point) {
/**
点击空白处须收回
*/
dismiss(animated: true, completion: nil)
}
}
}
原文地址:https://blog.csdn.net/weixin_42979360/article/details/122644687
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