弹出页（指定高度，自由拖动，点击空白包括状态栏触发）

本文介绍: iOS中对于指定高度弹出页面的设想1.首先需要指定弹出页面的高度：/** 页面高度 */ func g roundHe i g ht() -&g t; CGFloa t { return SlidePopViewCon t roll e r.windowSize.height-100 } /// 展示 class func show(_ controller: UIViewController) { let vc = SlidePopVie

1.首先需要指定弹出页面的高度：

/**
     页面高度
     */
    func groundHeight() -> CGFloat {
        return SlidePopViewController.windowSize.height-100
    }
    /// 展示
    class func show(_ controller: UIViewController) {
        let vc = SlidePopViewController()
        vc.modalTransitionStyle = .coverVertical
        vc.modalPresentationStyle = .overCurrentContext
        controller.present(vc, animated: false) {
            let size = SlidePopViewController.windowSize
            vc.view.frame = CGRect(x: 0, y: size.height, width: size.width, height: vc.groundHeight())
            UIView.animate(withDuration: 0.25, delay: 0, options: .curveEaseInOut, animations: {
                vc.view.frame = CGRect(x: 0, y: size.height-vc.groundHeight(), width: size.width, height: vc.groundHeight())
            }, completion: nil)
        }
    }

2.添加控制滑动手势：

let gesture = UIPanGestureRecognizer(target: self, action: #selector(slidePanAction(_:)))
        gesture.delegate = self
        view.addGestureRecognizer(gesture)

3.点击空白处包括状态栏收回：

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        if let point = touches.first?.location(in: keyWindow) {
            if !view.frame.contains(point) {
                /**
                 点击空白处须收回
                 */
                dismiss(animated: true, completion: nil)
            }
        }
    }