map优化对象数组

const citydate3 = ref([
  {
    text: now.getFullYear() - 1,
    id: 0,
    children: [
      { text: "全年", id: 0 },
      { text: 1, id: 1 },
      { text: 2, id: 2 },
      { text: 3, id: 3 },
      { text: 4, id: 4 },
      { text: 5, id: 5 },
    ],
  },
  {
    text: now.getFullYear(),
    id: 1,
    children: [
      { text: "全年", id: 0 },
      { text: 1, id: 1 },
      { text: 2, id: 2 },
      { text: 3, id: 3 },
      { text: 4, id: 4 },
      { text: 5, id: 5 },
    ],
  },
  {
    text: now.getFullYear() + 1,
    id: 3,
    children: [
      { text: "全年", id: 0 },
      { text: 1, id: 1 },
      { text: 2, id: 2 },
      { text: 3, id: 3 },
      { text: 4, id: 4 },
      { text: 5, id: 5 },
    ],
  },
]);

这是一个日期 picker 组件的数据，外层text代表年份，内层text代表那一年的月份，id均为index，下面运用map 方法进行改写

const citydate3 = ref(
  [now.getFullYear() - 1, now.getFullYear(), now.getFullYear() + 1].map((text, index) => ({
    text,
    id: index,
    children: ["全年", 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12].map((text, index) => ({
      text,
      id: index,
    })),
  })),
);

其实 map 解析数组和fo r 循环有点像，数组解析出来的每一项作为text，in dex为每一项的索引
现已知外层索引为1，内层索引为12，你可以使用以下方法访问外层和内层的text

const pickok = () => {
  //获取外层对象
  const obj1 = citydate3.value.find((obj) => obj.id === 1);
  //获取内层对象
  const obj2 = obj1.children.find((obj) => obj.id === 6);
  console.log(obj1.text, obj2.text);
};