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本文介绍: 最大化城市的最小电量（二分+前缀和+差分数组+贪心）礼盒的最大甜蜜度（二分）

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最大化城市的最小电量（二分+前缀和+差分 数组+贪心）

class Solution:
    def maxPower(self, stations: List[int], r: int, k: int) -&gt; int:
        n = len(stations)
        sum = list(accumulate(stations, initial=0))
        for i in range(n):
            stations[i] = sum[min(i + r + 1, n)] - sum[max(i - r, 0)]

        def check(target):
            diff = [0] * n
            sum_d = need = 0
            for i, x in enumerate(stations):
                sum_d += diff[i]
                m = target - x - sum_d
                if m &gt; 0:
                    need += m
                    if need &gt; k:
                        return False
                    sum_d += m
                    if i + r * 2 + 1 &lt; n:
                        diff[i + r * 2 + 1] -= m
            return True

        left = min(stations)
        right = left + k
        while left &lt; right:
            mid = (left + right + 1) // 2
            if check(mid):
                left = mid
            else:
                right = mid - 1
        return left

礼盒的最大甜蜜度（二分）

链接

class Solution:
    def maximumTastiness(self, price: List[int], k: int) -&gt; int:
        n = len(price)
        price.sort()
        def check(x):
            start, cnt = price[0], 1
            for i in range(1, n):
                if price[i] - start &gt;= x:
                    cnt += 1
                    start = price[i]
            return cnt &gt;= k
        l, r = 0, (price[-1] - price[0]) // (k - 1) + 1
        while l < r:
            mid = (l + r + 1) &gt;&gt; 1
            if check(mid):
                l = mid
            else:
                r = mid - 1
        return l