本文介绍: 【代码】MySQL综合实操练习题。
目录
6.找出部门10中所有人事部长和部门20中所有办事员的详细资料
3.查询出每个雇员的编号、姓名、基本工资、职位、领导的姓名、部门名称及位置
4.列出在部门”销售部”工作的员工的姓名，假定不知道销售部的部门编号
6.列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金
5.要求统计出每个部门的详细信息，并且要求这些部门的平均工资高于2000
一、创建表格
CREATE TABLE dept (
deptno INT(2) NOT NULL COMMENT '部门编号',
dname VARCHAR (15) COMMENT '部门名称',
loc VARCHAR (20) COMMENT '地理位置'
);
-- 添加主键
ALTER TABLE dept ADD PRIMARY KEY (deptno);
-- 添加数据
INSERT INTO dept (deptno,dname,loc)VALUES (10,'财务部','高新四路');
INSERT INTO dept (deptno,dname,loc)VALUES (20,'人事部','科技二路');
INSERT INTO dept (deptno,dname,loc)VALUES (30,'销售部','长安区');
INSERT INTO dept (deptno,dname,loc)VALUES (40,'运输部','雁塔区');
-- ---------------------------------------------------------------
CREATE TABLE emp(
empno INT(4) NOT NULL COMMENT '员工编号',
ename VARCHAR(10) COMMENT '员工名字',
job VARCHAR(10) COMMENT '职位',
mgr INT(4) COMMENT '上司',
hiredate DATE COMMENT '入职时间',
sal INT(7) COMMENT '基本工资',
comm INT(7) COMMENT '补贴',
deptno INT(2) COMMENT '所属部门编号'
);
-- 添加主键
ALTER TABLE emp ADD PRIMARY KEY (empno);
-- 添加外键约束
ALTER TABLE emp ADD CONSTRAINT f_ed_key
FOREIGN KEY (deptno)
REFERENCES dept(deptno);
INSERT INTO `emp` VALUES('7369','张倩','办事员','7902','2002-12-17','820',NULL,'20');
INSERT INTO `emp` VALUES('7499','刘博','售货员','7698','1992-02-20','1900','300','30');
INSERT INTO `emp` VALUES('7521','李兴','售货员','7698','1995-07-22','1250','500','30');
INSERT INTO `emp` VALUES('7566','李雷','人事部长','7839','1991-04-02','975',NULL,'20');
INSERT INTO `emp` VALUES('7654','刘浩','售货员','7698','1991-09-28','1250','1400','30');
INSERT INTO `emp` VALUES('7698','刘涛','销售部长','7839','1997-05-01','2850',NULL,'30');
INSERT INTO `emp` VALUES('7782','华仔','人事部长','7839','1995-06-09','2450',NULL,'10');
INSERT INTO `emp` VALUES('7788','张飞','人事专员','7566','1998-04-19','3000',NULL,'20');
INSERT INTO `emp` VALUES('7839','马晓云','董事长',NULL,'1991-11-17','5000',NULL,'10');
INSERT INTO `emp` VALUES('7844','马琪','售货员','7698','1996-09-08','1500','0','30');
INSERT INTO `emp` VALUES('7876','李涵','办事员','7788','1997-05-23','1100',NULL,'20');
INSERT INTO `emp` VALUES('7900','李小涵','销售员','7698','1993-2-13','950',NULL,'30');
INSERT INTO `emp` VALUES('7902','张三','人事组长','7566','1992-10-08','3000',NULL,'20');
INSERT INTO `emp` VALUES('7934','张三丰','人事长','7782','1997-06-23','1300',NULL,'10');
-- ---------------------------------------------------------------------
CREATE TABLE salgrade(
grade INT (10) COMMENT '工资等级',
losal INT (10) COMMENT '最低限额',
hisal INT (10) COMMENT '最高限额'
)
INSERT INTO salgrade (grade, losal, hisal)VALUES (1, 700, 1200);
INSERT INTO salgrade (grade, losal, hisal)VALUES (2, 1201, 1400);
INSERT INTO salgrade (grade, losal, hisal)VALUES (3, 1401, 2000);
INSERT INTO salgrade (grade, losal, hisal)VALUES (4, 2001, 3000);
INSERT INTO salgrade (grade, losal, hisal)VALUES (5, 3001, 9999);二、单表查询
1.选择部门30中的所有员工
select * from emp where deptno = 30;2.列出所有办事员的姓名，编号和部门编号
select ename, empno, deptno from emp where job = "办事员";3.找出佣金高于薪金的员工
select * from emp where comm > sal;4.找出没有佣金的员工
select * from emp where comm is null;5.找出佣金高于薪金的60%的员工
select * from emp where comm > sal * 0.6;6.找出部门10中所有人事部长和部门20中所有办事员的详细资料
select * from emp
where ((deptno = 10 and job = "人事部长") or (deptno = 20 and job = "办事员"));7.找出收取佣金的员工
select * from emp where comm is not null;8.找出不收取佣金或收取的佣金低于100的员工
select * from emp where comm is null or comm < 100;9.找出姓张的员工的信息
select * from emp where ename like "张%";10.显示员工的姓名和受雇日期,新的员工排在最前面
select ename, hiredate from emp order by hiredate desc;11.按工作的降序排序,若工作相同则按薪金排序
select * from emp
order by job, sal;12.查出不姓刘的员工的信息
select * from emp where ename not like "刘%";13.取出姓李的员工
select * from emp where ename like "李%";三、多表查询
1. 查询出每一位雇员的编号、姓名、职位、部门名称、位置
select empno, ename, job, dname, loc
from emp e
join dept d
on e.deptno = d.deptno;2.要求查询出每一位雇员的姓名、职位、领导的姓名
select a.ename, a.job, b.ename leader
from emp a
join emp b
on a.mgr = b.empno;3.查询出每个雇员的编号、姓名、基本工资、职位、领导的姓名、部门名称及位置
select c.empno, c.ename, c.sal, c.job, c.leader, dname, loc
from (
select a.*, b.ename leader
from emp a
join emp b
on a.mgr = b.empno) c
join dept d
on c.deptno = d.deptno;4.列出在部门”销售部”工作的员工的姓名，假定不知道销售部的部门编号
select ename
from emp e
join dept d
on e.deptno = d.deptno
where dname = "销售部";5.列出与”李兴”从事相同工作的所有员工
select *
from emp
where job = (
select job from emp where ename = "李兴"
);6.列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金
select ename, sal
from emp
having sal > (select max(sal) from emp where deptno = 30); 7.列出受雇日期早于其直接上级的所有员工
select a.ename , a.hiredate, b.ename, b.hiredate
from emp a
join emp b
on a.mgr = b.empno
where a.hiredate < b.hiredate;四、分组函数查询
1.按照部门编号分组，求出每个部的人数，平均工资
select deptno, sum(empno) 人数, avg(sal) 平均工资
from emp
group by deptno;2.按照职位分组，求出每个职位的最高和最低工资
select job, max(sal), min(sal)
from emp
group by job;3.计算出每个各职位的平均工资
select job, avg(sal)
from emp
group by job;4.查询出每个部门的名称、部门的人数、平均工资
select dname, count(*), avg(sal)
from emp e
left join dept d
on e.deptno = d.deptno
group by e.deptno;5.要求统计出每个部门的详细信息，并且要求这些部门的平均工资高于2000
select d.*, avgsal
from (
select deptno, avg(sal) avgsal
from emp
group by deptno
having avgsal > 2000) a
join dept d
on d.deptno = a.deptno;6.要求查询出工资比华仔还要高的全部雇员信息
select *
from emp
where sal > (select sal from emp where ename = "华仔");7.要求查询出高于公司平均工资的全部雇员信息
select *
from emp
where sal > (select avg(sal) from emp);8.查询出每个部门的编号、名称、位置、部门人数、平均工资
select d.deptno, dname, loc, count(*), avg(sal)
from dept d
join emp e
on d.deptno = e.deptno
group by d.deptno;9.列出至少有一个员工的所有部门
select dname, count(*) cnt
from emp e
join dept d
on d.deptno = e.deptno
group by d.deptno
having cnt >= 1;五、等级查询
1.查询每个工资等级各有多少员工
select grade, count(*)
from emp
join salgrade
where sal between losal and hisal
group by grade;2.查询部门中（所有人）的平均工资等级
select dname, grade
from(
select dname, avg(sal) avg_s
from emp e
join dept d
on e.deptno = d.deptno
group by d.deptno) c
join salgrade
on avg_s between losal and hisal;原文地址:https://blog.csdn.net/weixin_71169037/article/details/135713277
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